2011/7/21 mahendra1 <mahendra.gajera@...2640...>:
This is my drawing file : http://old.nabble.com/file/p32104728/drawing-1.svg drawing-1.svg With the use of your code i can get this output http://old.nabble.com/file/p32104728/RealOutPut.txt RealOutPut.txt This is real coordinate of the the object.
Here I need the output like http://old.nabble.com/file/p32104728/RequireOutPut.txt RequireOutPut.txt
The path in your drawing is written using relative commands (e.g. l instead of L). The coordinates after each command are relative to the last point. Inkscape does not have any code that would give you those coordinates - everything is converted to absolute coordinates when reading the path - and I'm not sure you really want them, because they're not very useful, except for writing a shorter path string.
If you always want relative coordinates, you can compute them by iterating over a PathVector.
for (Geom::PathVector::iterator i = pathv.begin(); i != pathv.end(); ++i) { for (Geom::Path::const_iterator j = i->begin(); j != i->end(); ++j) { Geom::Point relative = j->finalPoint() - j->initialPoint(); fprintf(fp, "%f %f\n", relative[Geom::X], relative[Geom::Y]); } }
If you also want the relative coordinates of Bezier control points: BezierCurve const *b = dynamic_cast<BezierCurve const *>(&*j); if (b) { std::vectorGeom::Point control_points = b->points(); /// do something with those points /// control_points[0] is the start point of the curve }
If you want to retrieve the coordnates as written in the path string - regardless of whether it was a relative or absolute command - you will need to use string operations (e.g. write your own parser with Ragel).
Regards, Krzysztof