Re: [Inkscape-devel] bug at bezier-utils.cpp

On Tue, Jul 12, 2005 at 12:50:35PM -0300, João Rafael Nicola wrote:

Using floating point number the following 'then' branch will not necessarily execute:

{   double x,y;
    x = 5.0;
    y = sqrt(25.0); //or another operation resulting in '5'
    if ( (x/y) == 1.0) {
        printf("This message may appear or may not.\n");
    }
}

The above code isn't a good example because the most likely reason for inequality would be sqrt resulting in a number not exactly equal to 5.

Anyway, I've now added some code to bezier-utils.cpp intended to deal with the case that x / x != 1.0 (despite x being isFinite and non-zero).

Can you cvs up and tell me if it still produces any messages (and what the message says, if it does produce a message) ?

Thanks,

pjrm.