Johan. Thanks for the tip.
Cheers, Jabier.



El mar, 01-07-2014 a las 23:03 +0200, Johan Engelen escribió:

> Hi Jabier,
>    I'm not 100% sure, but you may consider to always use floating point
> numbers for the type of calculation you are doing, unless you are sure
> you want integer calculation. So then it becomes:
>
> (4./3.) * (sqrt(2.) - 1.)
>
> regards,
>    Johan
>
>
> On 1-7-2014 9:41, Jabiertxo Arraiza Cenoz wrote:
> > Thanks Nathan. I just read it in a book but dont remeber when
> > necessary :(.
> > And thanks for the operator precedence tip.
> >
> > Cheers, Jabier.
> >
> >
> > El mar, 01-07-2014 a las 07:59 +1000, Nathan Hurst escribió:
> >> On Mon, Jun 30, 2014 at 11:56:15PM +0200, Jabiertxo Arraiza Cenoz wrote:
> >>> Hi to all.
> >>>
> >>> I try this in my debian calculator:
> >>> "4 / 3 * (sqrt(2) - 1)" and return 0,55228475
> >>> in C++ return 0.414214
> >>>
> >>> I want 0,55228475.
> >>> Where i lost? I have the cmath header
> >> 4/3 = 1 because the type of both arguments is int. 4.0/3 fixes your
> >> problem.  I would put (4./3) * sqrt() because operator precedence for
> >> divide is not always clear.
> >>
> >> njh
> >
> >
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