Help with CubicBezier in a closed Geom::Path::const_iterator
Hi. I have a problem. Its this: T get the last subpath of a Geom::Path::const_iterator whith a this options: end_open(), end(), end_default(), end_closed() and this subpath is not degenerated at the end. But never get a CubicBezier from the last subpath. Anybody can help me?
Thanks in advance.
On 23-2-2013 20:32, Jabiertxo Arraiza Cenoz wrote:
Hi. I have a problem. Its this: T get the last subpath of a Geom::Path::const_iterator whith a this options: end_open(), end(), end_default(), end_closed() and this subpath is not degenerated at the end. But never get a CubicBezier from the last subpath. Anybody can help me?
I don't understand your exact question, but perhaps this will help.
General advice: *only* use end_open(), end_closed(), or end_default(). 2geom offers an end() method for paths, but do not use it; it makes the code difficult to read because end() returns end_open().
end_open() returns the last segment assuming that the path is not closed.
end_closed() always returns a ClosingSegment (which is a LineSegment). It assumes the path is closed. (even if it is not closed). The returned segment is a straight line from start to end, closing the path. For paths that look curved, this segment will probably be degenerate, i.e. infinitely small.
end_default(): returns end_open() for open paths, and returns end_closed() for closed paths.
Cheers, Johan
El dom, 24-02-2013 a las 23:22 +0100, Johan Engelen escribió:
On 23-2-2013 20:32, Jabiertxo Arraiza Cenoz wrote:
Hi. I have a problem. Its this: T get the last subpath of a Geom::Path::const_iterator whith a this options: end_open(), end(), end_default(), end_closed() and this subpath is not degenerated at the end. But never get a CubicBezier from the last subpath. Anybody can help me?
I don't understand your exact question, but perhaps this will help.
General advice: *only* use end_open(), end_closed(), or end_default(). 2geom offers an end() method for paths, but do not use it; it makes the code difficult to read because end() returns end_open().
end_open() returns the last segment assuming that the path is not closed.
end_closed() always returns a ClosingSegment (which is a LineSegment). It assumes the path is closed. (even if it is not closed). The returned segment is a straight line from start to end, closing the path. For paths that look curved, this segment will probably be degenerate, i.e. infinitely small.
end_default(): returns end_open() for open paths, and returns end_closed() for closed paths.
Cheers, Johan
Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb _______________________________________________ Inkscape-devel mailing list Inkscape-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/inkscape-devel
Thanks very much Johan. My english is bad but i attempt to explain the problem.
While coding, i decide i need to use "end_open()", when read your words it confirm me.
Why i decide use "end_open" in closed paths? because y want to know the cubicBezier of the last visible path, ignoring the extra seg who closed the path. Is this ok?
The problem is the bezier curve in [2] always return value at [3].
Put code of the function.
Hi, and thanks.
El lun, 25-02-2013 a las 12:29 +0100, Jabiertxo Arraiza Cenoz escribió:
El dom, 24-02-2013 a las 23:22 +0100, Johan Engelen escribió:
On 23-2-2013 20:32, Jabiertxo Arraiza Cenoz wrote:
Hi. I have a problem. Its this: T get the last subpath of a Geom::Path::const_iterator whith a this options: end_open(), end(), end_default(), end_closed() and this subpath is not degenerated at the end. But never get a CubicBezier from the last subpath. Anybody can help me?
I don't understand your exact question, but perhaps this will help.
General advice: *only* use end_open(), end_closed(), or end_default(). 2geom offers an end() method for paths, but do not use it; it makes the code difficult to read because end() returns end_open().
end_open() returns the last segment assuming that the path is not closed.
end_closed() always returns a ClosingSegment (which is a LineSegment). It assumes the path is closed. (even if it is not closed). The returned segment is a straight line from start to end, closing the path. For paths that look curved, this segment will probably be degenerate, i.e. infinitely small.
end_default(): returns end_open() for open paths, and returns end_closed() for closed paths.
Cheers, Johan
Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb _______________________________________________ Inkscape-devel mailing list Inkscape-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/inkscape-devel
Thanks very much Johan. My english is bad but i attempt to explain the problem.
While coding, i decide i need to use "end_open()", when read your words it confirm me.
Why i decide use "end_open" in closed paths? because y want to know the cubicBezier of the last visible path, ignoring the extra seg who closed the path. Is this ok?
The problem is the bezier curve in [2] always return value at [3].
Put code of the function.
Hi, and thanks.
Sorry the code:
On 25-2-2013 13:41, Jabiertxo Arraiza Cenoz wrote:
El lun, 25-02-2013 a las 12:29 +0100, Jabiertxo Arraiza Cenoz escribió:
El dom, 24-02-2013 a las 23:22 +0100, Johan Engelen escribió:
On 23-2-2013 20:32, Jabiertxo Arraiza Cenoz wrote:
Hi. I have a problem. Its this: T get the last subpath of a Geom::Path::const_iterator whith a this options: end_open(), end(), end_default(), end_closed() and this subpath is not degenerated at the end. But never get a CubicBezier from the last subpath. Anybody can help me?
I don't understand your exact question, but perhaps this will help.
General advice: *only* use end_open(), end_closed(), or end_default(). 2geom offers an end() method for paths, but do not use it; it makes the code difficult to read because end() returns end_open().
end_open() returns the last segment assuming that the path is not closed.
end_closed() always returns a ClosingSegment (which is a LineSegment). It assumes the path is closed. (even if it is not closed). The returned segment is a straight line from start to end, closing the path. For paths that look curved, this segment will probably be degenerate, i.e. infinitely small.
end_default(): returns end_open() for open paths, and returns end_closed() for closed paths.
Cheers, Johan
Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb _______________________________________________ Inkscape-devel mailing list Inkscape-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/inkscape-devel
Thanks very much Johan. My english is bad but i attempt to explain the problem.
While coding, i decide i need to use "end_open()", when read your words it confirm me.
Why i decide use "end_open" in closed paths? because y want to know the cubicBezier of the last visible path, ignoring the extra seg who closed the path. Is this ok?
The problem is the bezier curve in [2] always return value at [3].
Put code of the function.
Hi, and thanks.
Sorry the code:
The closing segment is not always infinitely small!! So it is better to loop until end_default() and check for each segment (also intermediate segments) if they are degenerate or not (using Curve::isDegenerate()). cubic[2] == cubic[3] for many different paths? Create a circle with the circle tool and do "object to path". That should create a nice path where cubic[2] != cubic[3].
(A general comment about your code: don't declare all variables at the start of the function. It makes the code harder to read. It's also better to reduce the scope of variables by only declaring them within the {}-block they are used.)
Ciao, Johan
El jue, 28-02-2013 a las 23:32 +0100, Johan Engelen escribió:
On 25-2-2013 13:41, Jabiertxo Arraiza Cenoz wrote:
El lun, 25-02-2013 a las 12:29 +0100, Jabiertxo Arraiza Cenoz escribió:
El dom, 24-02-2013 a las 23:22 +0100, Johan Engelen escribió:
On 23-2-2013 20:32, Jabiertxo Arraiza Cenoz wrote:
Hi. I have a problem. Its this: T get the last subpath of a Geom::Path::const_iterator whith a this options: end_open(), end(), end_default(), end_closed() and this subpath is not degenerated at the end. But never get a CubicBezier from the last subpath. Anybody can help me?
I don't understand your exact question, but perhaps this will help.
General advice: *only* use end_open(), end_closed(), or end_default(). 2geom offers an end() method for paths, but do not use it; it makes the code difficult to read because end() returns end_open().
end_open() returns the last segment assuming that the path is not closed.
end_closed() always returns a ClosingSegment (which is a LineSegment). It assumes the path is closed. (even if it is not closed). The returned segment is a straight line from start to end, closing the path. For paths that look curved, this segment will probably be degenerate, i.e. infinitely small.
end_default(): returns end_open() for open paths, and returns end_closed() for closed paths.
Cheers, Johan
Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb _______________________________________________ Inkscape-devel mailing list Inkscape-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/inkscape-devel
Thanks very much Johan. My english is bad but i attempt to explain the problem.
While coding, i decide i need to use "end_open()", when read your words it confirm me.
Why i decide use "end_open" in closed paths? because y want to know the cubicBezier of the last visible path, ignoring the extra seg who closed the path. Is this ok?
The problem is the bezier curve in [2] always return value at [3].
Put code of the function.
Hi, and thanks.
Sorry the code:
The closing segment is not always infinitely small!! So it is better to loop until end_default() and check for each segment (also intermediate segments) if they are degenerate or not (using Curve::isDegenerate()). cubic[2] == cubic[3] for many different paths? Create a circle with the circle tool and do "object to path". That should create a nice path where cubic[2] != cubic[3].
(A general comment about your code: don't declare all variables at the start of the function. It makes the code harder to read. It's also better to reduce the scope of variables by only declaring them within the {}-block they are used.)
Ciao, Johan
Thanks johan for your gratefoul help. I put this new code http://pastebin.com/4nQxpLH3 whith vars declared when strict necesary like you tell me. Finaly use this code from lpe-spiro.cpp to check the last path of a closed element is degenerated: 43-46 of the pastedbin.
And remove the use of curve_end. But still have the same problem. I explain it:
The "last segment" is a cubic bezier curve, but the code alwais go over the line 103 -not cubic- instead the previous cubic check -101-.
Maybe can be related to the TODO comment in line 1120 of path-manipulator.cpp? If change it from cubic to bezier the problem still here.
Here is a pic whith the problem on close node http://picturepush.com/public/12331862
Hi, Jabier.
participants (2)
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Jabiertxo Arraiza Cenoz -
Johan Engelen