Hi,<br><br>Note: Speculation follows...<br><br>Situations like this should be handled well by SVG&#39;s Vector Effects once we implement them. It will allow faux subtraction and union with objects. Given that you can apply different Filter Effects to clones, it would make sense that the Vector Effects will work in the same way (though I do not see any specific mention in the proposed spec). No, there is no current ETA to implementing them yet. :)<br>

<br>Cheers,<br>Josh<br><br><br><br><div class="gmail_quote">On Fri, Apr 15, 2011 at 12:57 AM, donn <span dir="ltr">&lt;<a href="mailto:donn.ingle@...155...">donn.ingle@...155...</a>&gt;</span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex;">

Hi,<br>
Here&#39;s a situation:<br>
You have an original path, say a seagull. You make a clone for someplace<br>
else. But, you need that clone to *act* more like an actual path than a<br>
clone. Say you want it to punch-out (subtract) from some other path.<br>
Now you could use the original seagull path, but that can be dangerous<br>
because it&#39;s your master drawing. To punch out some other path, you<br>
would have to *move* the &#39;master&#39; to the precise position and then make<br>
a copy and fiddle with z-order and then do the subtraction op.<br>
And, say you are doing this many times - adjusting as you go.<br>
<br>
Now, if I could make a &quot;path clone&quot; and use it like a tool, that would<br>
solve the problem. I alter the master, the path-clone changes. I<br>
re-punch the other path. Loop until satisfied.<br>
<br>
There are other situations I have found where I wish a clone could be a<br>
path and still be a clone, I just can&#39;t recall them.<br>
<br>
Would there be some way to drive this by Python? I could point a path at<br>
a clone (or the master) and say &#39;take this shape&#39; (i.e. an update of the<br>
path to match the source). It would be great if the two could remain<br>
linked and auto-update as the source changes shape.<br>
<br>
\d<br>
<br>
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