Hey,

Thanks for the reply. I came up with this, trying to extract all the rectangles from the svg:

import sys sys.path.append('/usr/share/inkscape/extensions') import inkex from simplestyle import *

class RectOutput(inkex.Effect): def __init__(self): inkex.Effect.__init__(self) def output(self): for r in self.rects: print "Rectangle occupying: ", r.attrib.get("x"),",",r.attrib.get("y")," - ",r.attrib.get("width"),",",r.attrib.get("height")

def effect(self): dom_svg = self.document.getroot() self.rects = dom_svg.xpath('//svg:rect',namespaces=inkex.NSS) self.circles = dom_svg.xpath('//svg:circle',namespaces=inkex.NSS) self.polygons = dom_svg.xpath('//svg:polygon',namespaces=inkex.NSS)

if __name__ == "__main__": e = RectOutput() e.affect()

I get something, but I am unsure what its meaning is. What I want to get: - The center of the rectangle - Its width and height - Its rotation angle

I am noticing that when I am rotating my rectangle, the "x" and "y" component change. So what exactly are there meaning? How do I get the rotation angle?

Thanks! Nathan

On 03/20/2011 03:59 AM, Alvin Penner wrote:

in the directory \Inkscape\share\extensions\ there are some examples of Python exporters, for example, .dxf, .hpgl, .xaml

hth, Alvin Penner

OK, and how do I get this matrix? It does not seem to be an element of the rectangle itself ...

I am guessing that the transformation is hidden in some parent element of the rectangle. So using xpath is probably not the best way to find all rectangles. How can I iterate over all rectangles and also find the proper transformation while doing so?

Thanks! Nathan

On 03/20/2011 04:41 PM, Alvin Penner wrote:

the x and y coordinates are probably the coordinates of the upper left corner, so they will change when you rotate the object. The rotation angle will often be embedded in an affine transform element that will look like this : matrix(0.90791043,-0.41916422,0.41916422,0.90791043,0,0)

Alvin