3 Sep
2008
3 Sep
'08
8:47 p.m.
On Mon, 2008-09-01 at 15:38 -0700, Jon A. Cruz wrote:
Well, the general problem here is if not everything comes through the exact same path for each and every point, then the bits representing the same string might actually be different.
Fundamentally, the start and end points of adjacent Curves represent the *same* logical point and their binary equivalence ought to be preserved across transformations (at least those which are applied to both curves as part of a larger unit).
-mental