Symbol edition and reuse
by Xaviju Julián
Hi,
As suggested in the new features section I'd like to see the community
opinion on a possible feature suggestion.
As a heavy user of the symbols feature for web design I tend to save many
UI portions of my design as symbols and reuse them across many different
documents.
Sometimes I need to edit one of those symbols and I'd like all documents
that are referencing that symbol to update. Same behavior as when I update
the original symbol SVG code, all references will keep using that symbol,
but updated.
Right now, the only way I found the inkscape UI has to edit a symbol is to
`unplug` (sorry don't know the english word) it from its reference, but
that does not allow me to reuse and update.
Do this make sense to you? Am I missing something?
Thanks,
Xavi
5 years, 5 months
- 3
- 2
misunderstood tiled clones issue
by brynn
Hi Friends,
Someone recently has posted in a forum, asking why the first array
created by Tiled Clones dialog is deleted, when the 2nd array is created (using
the same parent object). http://www.inkscapeforum.com/viewtopic.php?f=5&t=33037
Because this is what I previously understood the Remove button is
supposed to do, I thought it must be a bug. However searching LP has not turned
up any existing bug report (not unless its title contains technical language
that I don't understand, or that doesn't really describe the issue).
I'm on Windows, but other operating systems are represented in the forum
topic.
I tested going back to version 0.47.3, and the same behavior is seen
there. So since it seems to be long standing, and not reported, I have to think
it's either intended behavior, or at least not a bug.
Oh interesting! It seems the first array is deleted /whenever/ a 2nd
array is created with the same parent (not just when the 2nd array immediately
follows the first)! Because I did this (with all default settings):
1 - Object A: 2 x 2 array
2 - Move all the clones away from the array area (to easily notice that they are
deleted when the 2nd array is created, and not just covered up by the 2nd
array).
3 - Object B: 3 x 3 array
4 - Object A: 4 x 4 array -- This removes all the clones from the 2 x 2 array of
object A; leaves the 3 x 3 array of object B alone, and creates the new 4 x 4
array of object A.
If there's a reason for this, could someone explain, in a not too
technical way?
Thank you very much,
brynn
5 years, 5 months
- 1
- 0
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